Page 49 - matematica-viii
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ℝ
                                                                         c
                                                                         ul a
                                                                            ebric în
                                                                        l

                                                                       C
                                                                        a
                                                                           lg
                                                          Capitolul 2
                                                                                                             47
                                                          UNIT A TEA  2  Calcul algebric în  ℝ               47
                                                          Recapitulare





            1. Calculați:                                      6. Calculați, folosind formulele de calcul prescurtat:

            a)  4  x   + 5x–8 +  x   –1–7x ;                   a)   (4x − 1)   −   (3x + 1)  (3x − 1) −    ( x   − 2x)   ;











                 2
                                                                        2




                           2
                                                                                                2

                                                                                           2


                                                                                 _
                                                                                          _
                                                                    _
                                                                          _
                                                                                                          _


                                                                          7)





                                                                                 6










                                                                    2

                                                                                          6



            b)  7  x   –2x–5–3  x   + 6x + 8 ;                 b)   (2   √   x −   √     −   (  √   x − 2)  (  √   x + 2) − 2x  (x − 2   √ 14   ) ;

                                                                            2

                           2
                 2


                                                                          2          2           2
                                                                       2 _
                                                                                        4 _
                                                                                  3 _
                                                                  4 _
                                                                                              2 _
                                                                              1 _








            c)  x   –4x + 7–2  x   + 5x–3  x   –4 + 6  x   ;    c)       x   +     x    +   (     x −      )    −        x   −     x    ;










                           3




















                                   2






                                           3


               2

                                                                                           2
                                                                    2







                                                                              2
                                                                       5 )
                                                                                  2
                                                                                              5 )
                                                                (5
                                                                                       (5
                                                                                                   _
                                                                                             _
                                                                   _
                                                                                _
                                                                                      _
               3 _
                        7 _





            d)     a + 2ay −     ay + 4a ;                     d)   (  √   x + 3)   −   (2   √   x −   √    (2   √   x +   √













                                                                                             5
                                                                   5




                                                                                      3) ⋅

                                                                                                   3) +



                                                                                5

                                                                          2
               5
                        2
                                                                    _



            e)  13, 4  x   –5, 24 + 3, 61x + 4, 15–6, 71  x   + 4, 9x ;  +    (3   √   x − 1)   ;
                                             2
                    2



                                                                    5





                                                                          2
                             0, 3
              0, 5
              _
                     3 _
                             _
            f)      x   −     x +  x   +     x + 5 ;           e)    [  (6x − 1)  (3x + 2) −   (2x − 5)  (9x + 1)  ]  [  (x − 4)  (x + 3) −


















                  2
                          2








               2
                     2
                              4
                             7 _
                                     3 _
                        7 _
                                 1 _
               5 _
                    3 _











            g)      x   +     x −      x   +     −     x +     ;        −   (x + 4)  (x − 5)  ] .


















                 2
                          2
               2
                                2
                             5
                                     2
                    4
                        3


            h)  3,   (1)  x   –5, 2x + 4, 3  (2) + 6,   (3) x–5, 6  x   + 7, 1 .  7. Descompuneți expresiile în factori:




                    2
                                                2

            2. Calculați:                                      a)  7x  (1–2x) –5  (1–2x) ;




            a)  2x + 3x − 2 + 4x − (5x + 4 ) + (3x + 2) ;      b)  32  x   –8  x   + 16  x   –4  x   ;

                                                                    5



                                                                         4
                                                                                    2

                                                                               3

















                                                                    4
                                                                                          4

            b)  ab + 2 − (3ab − 5 ) + (4ab + 1 ) − ab − 2 ;    c)  6  a    b    c   –9  a    b    c   + 12  a    b    c   ;

                                                                            2

                                                                                      3
                                                                                        3

                                                                       3


                                                                      5

                                                                                2

                                                                              4


            c)  3  (4x–6) –4x  (x + 3) ;                       d)   (3–2x)  (x–3) –  (x–3)  (1–4x) ;






            d)  4x ·   (x–5) –3 ·   ( x   + 3x–1) + 2 ·   (2x –1) ;    e)   (x–3)  (2x–5) –  (3–x)  (4–3x) ;

                            2





            e)   (16  x   –5  x   + 3x)  :   (0, 5x) ;         f)  12  x   –8  x   –15x + 10 ;



                                                                    3

                                                                        2

                       2
                   3





















            f)   (6  a    x    y   –12  a    x    y   –9  a    x    y    )  :   (– 3  a    x    y    ) ;    g)   (2x–3)  –4x    (2x–3)   –5  (2x–3) ;












                                                                                  2






                                                                       3



                  2
                                     3
                      2
                           4
                             2
                               3
                                    3
                                               2
                                                   2
                                                 2
                                       3
                    3































            g)   (3  a    x   –5  a    x   + 6  a    x    )  :   (2  a    x    ) ;    h)   (2 − x)  + 2x    (2 − x)   − 5  (x–2) .

                                       4
                                2
                          3
                                                                                 2
                                                                       3
                  4
                    2
                                  4
                                         4
                        3


            h)  7  x    (x–2) –5x  (3  x   –6x–4) + 4  (2  x   –4  x   –5x + 3) .    8. Descompuneți expresiile în factori:




                             2
                 2
                                                2




                                           3
                                                                                               _




            3. Calculați:                                      a)  16–40x + 25  x   ;   b)  3  x   − 2   √   x + 1 ;


                                                                                               3



                                                                             2
                                                                                         2


            a)   (2  x   –3x–1)  (x–1) ;                       c)  81–4  x   ;       d)  16  x   –3 ;




                                                                       2


                                                                                          2

                  2
                 _   _        _     _      _    _        _









            b)   2   √   ⋅   (  √   − 2x) +   √   ⋅   (2   √   x + 3   √           2        6  )      e)   (4x–3)   –25 ;   f)  25  x   –   (2x–1)   ;
                 3

                                                                                                  2


                              6

                                                                       2




                                           3) −   √   ⋅   (8 − x   √     ;




                                                                                          2


                     3
                                    2

























            c)   ( x   +  x   +  x    )  (x–1) ;               g)   (6x–1)   –   (4x–3)   ;   h)     (7x–4)   –   (2x–3)   ;
                        2
                                                                                             2
                                                                               2
                    3
                                                                                                      2
                                                                       2
                4
                                                                         _





            d)   [–5x ·   (8  x   –4  x    ) –10x ·   (6  x   –4x)  ]  :   (–20  x    ) ;    i)  9  x   − 6   √    x   + 2 .





                                                                         2



                       4

                                                                           2
                                                                   4
                                      2


                            3


                                                  2


            e)   ( x   –x + 1)  ( x   + x + 1) ;               9. Descompuneți expresiile în factori:




                         2

                2








            f)   [  (3  x   –2x–4) ·   (x–2) –  ( x   + 4x–8) ·   (x + 1)  ]  :   (8x) ;    a)  x   − x  y   +  x   y −  y   ;   b)  x   + 2  x   − 3x − 6 ;
                                   2
                  2















                                                                                        3

                                                                           2

                                                                                3
                                                                  3
                                                                                             2


                                                                       2



            g)   [2x + 1–  (x + 2)  ]  [3x–2–  (2x–3)  ] ;     c)  x   − 10x + 16 ;   d)  x   − 6x − 16 ;








                                                                  2
                                                                                        2
                   _    _         _        _      _


            h)     3   √           3           3(2x + 3   √           7           e)  9  x   − 6x − 15 ;   f)  16  x   − 8x − 24 ;
                                           7) + 3   √   x  (2x + 1) −
                    7(2   √   − x) − 2   √







                                                                   2
                                                                                          2
                   _

            – 6  x      √   .                                  g)  x   − 3x − 28 ;   h)  6  x   –3  x   –10x + 5 ;
                   7
                 2






                                                                                         3



                                                                                              2
                                                                  2

            4. Calculați aria unui pătrat care are perimetrul egal cu     i)  4  x   − 8  x   − 140x .




                                                                        2
                                                                   3

            4ab  metri,  a, b ∈ ℕ .                            10. Descompuneți expresiile în factori:








            5. Calculați, folosind formulele de calcul prescurtat:   a)   ( x   + x + 1)  ( x   + x + 3) + 1 ;

                                                                   2
                                                                            2


            a)   (2x–3)   ;           b)   (4x–3)  (4x + 3) ;           c)   (4x − 3)   ;    b)   ( x   –x + 2)  ( x   –x + 4) + 1 ;















                                                                   2
                                                                            2

                     2

                                                        2


                                            _
                                      _
                                       3




            d)     [0, (2 ) + 3x]   ;   e)     (  √   x +   √     ;    c)   ( x   –x)  ( x   –x + 5) − 6 ;

                                            5)









                                                                   2

                         2
                                              2

                                                                        2













            f)   (2x − 5)  (2x + 5) ;   g)   (0, 3x − 7, 3)  (0, 3x + 7, 3) ;    d)   ( x   − x + 1)   + 2 ⋅   ( x   − x + 1) − 3 .





                                                                                 2

                                                                   2

                                                                          2

                                      _
                                            _
                3 _
                    7 _
                        3 _
                            7 _




                                            5)







            h)       x −            x +        ;   i)    (  √   x +   √     − 10 .  Indicație. Folosiți substituții/notații convenabile.









                                      3







                                              2
                            6 )
               (4
                    6 )(4
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